Optimal. Leaf size=181 \[ -\frac{i a^6 \sqrt{a+i a \tan (c+d x)}}{6 d (a-i a \tan (c+d x))^3}-\frac{5 i a^5 \sqrt{a+i a \tan (c+d x)}}{48 d (a-i a \tan (c+d x))^2}-\frac{5 i a^4 \sqrt{a+i a \tan (c+d x)}}{64 d (a-i a \tan (c+d x))}-\frac{5 i a^{7/2} \tanh ^{-1}\left (\frac{\sqrt{a+i a \tan (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{64 \sqrt{2} d} \]
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Rubi [A] time = 0.108335, antiderivative size = 181, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.154, Rules used = {3487, 51, 63, 206} \[ -\frac{i a^6 \sqrt{a+i a \tan (c+d x)}}{6 d (a-i a \tan (c+d x))^3}-\frac{5 i a^5 \sqrt{a+i a \tan (c+d x)}}{48 d (a-i a \tan (c+d x))^2}-\frac{5 i a^4 \sqrt{a+i a \tan (c+d x)}}{64 d (a-i a \tan (c+d x))}-\frac{5 i a^{7/2} \tanh ^{-1}\left (\frac{\sqrt{a+i a \tan (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{64 \sqrt{2} d} \]
Antiderivative was successfully verified.
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Rule 3487
Rule 51
Rule 63
Rule 206
Rubi steps
\begin{align*} \int \cos ^6(c+d x) (a+i a \tan (c+d x))^{7/2} \, dx &=-\frac{\left (i a^7\right ) \operatorname{Subst}\left (\int \frac{1}{(a-x)^4 \sqrt{a+x}} \, dx,x,i a \tan (c+d x)\right )}{d}\\ &=-\frac{i a^6 \sqrt{a+i a \tan (c+d x)}}{6 d (a-i a \tan (c+d x))^3}-\frac{\left (5 i a^6\right ) \operatorname{Subst}\left (\int \frac{1}{(a-x)^3 \sqrt{a+x}} \, dx,x,i a \tan (c+d x)\right )}{12 d}\\ &=-\frac{i a^6 \sqrt{a+i a \tan (c+d x)}}{6 d (a-i a \tan (c+d x))^3}-\frac{5 i a^5 \sqrt{a+i a \tan (c+d x)}}{48 d (a-i a \tan (c+d x))^2}-\frac{\left (5 i a^5\right ) \operatorname{Subst}\left (\int \frac{1}{(a-x)^2 \sqrt{a+x}} \, dx,x,i a \tan (c+d x)\right )}{32 d}\\ &=-\frac{i a^6 \sqrt{a+i a \tan (c+d x)}}{6 d (a-i a \tan (c+d x))^3}-\frac{5 i a^5 \sqrt{a+i a \tan (c+d x)}}{48 d (a-i a \tan (c+d x))^2}-\frac{5 i a^4 \sqrt{a+i a \tan (c+d x)}}{64 d (a-i a \tan (c+d x))}-\frac{\left (5 i a^4\right ) \operatorname{Subst}\left (\int \frac{1}{(a-x) \sqrt{a+x}} \, dx,x,i a \tan (c+d x)\right )}{128 d}\\ &=-\frac{i a^6 \sqrt{a+i a \tan (c+d x)}}{6 d (a-i a \tan (c+d x))^3}-\frac{5 i a^5 \sqrt{a+i a \tan (c+d x)}}{48 d (a-i a \tan (c+d x))^2}-\frac{5 i a^4 \sqrt{a+i a \tan (c+d x)}}{64 d (a-i a \tan (c+d x))}-\frac{\left (5 i a^4\right ) \operatorname{Subst}\left (\int \frac{1}{2 a-x^2} \, dx,x,\sqrt{a+i a \tan (c+d x)}\right )}{64 d}\\ &=-\frac{5 i a^{7/2} \tanh ^{-1}\left (\frac{\sqrt{a+i a \tan (c+d x)}}{\sqrt{2} \sqrt{a}}\right )}{64 \sqrt{2} d}-\frac{i a^6 \sqrt{a+i a \tan (c+d x)}}{6 d (a-i a \tan (c+d x))^3}-\frac{5 i a^5 \sqrt{a+i a \tan (c+d x)}}{48 d (a-i a \tan (c+d x))^2}-\frac{5 i a^4 \sqrt{a+i a \tan (c+d x)}}{64 d (a-i a \tan (c+d x))}\\ \end{align*}
Mathematica [A] time = 1.00398, size = 129, normalized size = 0.71 \[ -\frac{i a^3 e^{-i (c+d x)} \sqrt{1+e^{2 i (c+d x)}} \left (e^{i (c+d x)} \sqrt{1+e^{2 i (c+d x)}} \left (26 e^{2 i (c+d x)}+8 e^{4 i (c+d x)}+33\right )+15 \sinh ^{-1}\left (e^{i (c+d x)}\right )\right ) \sqrt{a+i a \tan (c+d x)}}{384 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.402, size = 1088, normalized size = 6. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.24483, size = 813, normalized size = 4.49 \begin{align*} \frac{\sqrt{2}{\left (-8 i \, a^{3} e^{\left (6 i \, d x + 6 i \, c\right )} - 34 i \, a^{3} e^{\left (4 i \, d x + 4 i \, c\right )} - 59 i \, a^{3} e^{\left (2 i \, d x + 2 i \, c\right )} - 33 i \, a^{3}\right )} \sqrt{\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (i \, d x + i \, c\right )} + 15 \, \sqrt{\frac{1}{2}} \sqrt{-\frac{a^{7}}{d^{2}}} d \log \left (\frac{{\left (10 i \, \sqrt{\frac{1}{2}} \sqrt{-\frac{a^{7}}{d^{2}}} d e^{\left (2 i \, d x + 2 i \, c\right )} + 5 \, \sqrt{2}{\left (a^{3} e^{\left (2 i \, d x + 2 i \, c\right )} + a^{3}\right )} \sqrt{\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (i \, d x + i \, c\right )}\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{5 \, a^{3}}\right ) - 15 \, \sqrt{\frac{1}{2}} \sqrt{-\frac{a^{7}}{d^{2}}} d \log \left (\frac{{\left (-10 i \, \sqrt{\frac{1}{2}} \sqrt{-\frac{a^{7}}{d^{2}}} d e^{\left (2 i \, d x + 2 i \, c\right )} + 5 \, \sqrt{2}{\left (a^{3} e^{\left (2 i \, d x + 2 i \, c\right )} + a^{3}\right )} \sqrt{\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (i \, d x + i \, c\right )}\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{5 \, a^{3}}\right )}{384 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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